Consider the bottle-in-a-bottle problem in a previous problem set, summarized here.
The volume of the small bottle is 0.001 m\(^3\) and the volume of the big bottle is 0.01 m\(^3\). The initial state of the gas in the small bottle was \(p=106\) Pa and its temperature \(T=300\) K. Approximate the helium gas as an ideal gas of equations of state \(pV=Nk_BT\) and \(U=\frac32 Nk_BT\).
How many molecules of gas are initially in the small bottle? What is the final temperature of the gas after the pressures have equalized?
Compute the change of entropy \)\Delta S\( between the initial state (gas in the small bottle) and the final state (gas in both bottles, pressures equalized). Do not use the Sackur-Tetrode equation, use an alternative method.
Consider the adiabatic expansion of a simple ideal gas (adiabatic means that no energy is transfered by heating). The internal energy is given by \begin{align} U &= C_v T \end{align} where you may take \(C_v\) to be a constant---although for a polyatomic gas such as oxygen or nitrogen, it is temperature-dependent. The ideal gas law \begin{align} pV &= Nk_BT \end{align} determines the relationship between \(p\), \(V\) and \(T\). You may take the number of molecules \(N\) to be constant.
Use the first law to relate the inexact differential for work to the exact differential \(dT\) for an adiabatic process.
Find the total differential \(dT\) where \(T\) is a function \(T(p,V)\).
In the previous two sections, we found two formulas involving \(dT\). Use the additional definition of work \({\mathit{\unicode{273}}} W = -pdV\) to solve for the relationship between \(p\), \(dp\), \(V\) and \(dV\) for an adiabatic process.
A diesel engine requires no spark plug. Rather, the air in the cylinder is compressed so highly that the fuel ignites spontaneously when sprayed into the cylinder.
In this problem, you may treat air as an ideal gas, which satisfies the equation \(pV = Nk_BT\). You may also use the property of an ideal gas that the internal energy depends only on the temperature \(T\), i.e. the internal energy does not change for an isothermal process. For air at the relevant range of temperatures the heat capacity at fixed volume is given by \(C_V=\frac52Nk_B\), which means the internal energy is given by \(U=\frac52Nk_BT\).
Note: Looking up the formula in a textbook is not considered a solution at this level. Use only the equations given, fundamental laws of physics, and results you might have already derived from the same set of equations in other homework questions.
If the air is initially at room temperature (taken as \(20^{o}C\)) and is then compressed adiabatically to \(\frac1{15}\) of the original volume, what final temperature is attained (before fuel injection)?