Consider a spin-1/2 particle with a magnetic moment. At time \(t=0\), the state of the particle is \(\left|{\psi(t=0)}\right\rangle =\left|{+}\right\rangle \).
If the observable \(S_x\) is measured at time \(t=0\), what are the possible measurement values, and what is the probability of obtaining each value?
Instead of performing the above measurement, the system is allowed to evolve in a uniform magnetic field \(\vec{B}=B_0\, \hat y\). The Hamiltonian for a system in a uniform magnetic field \(\vec B=B_0\, \hat y\) is \(\hat H=\omega_0\, \hat S_y\). (You can treat \(\omega_0\) as a given parameter in your answers to the following two questions.)
What is the state of the system at the later time t (i.e., find \(|\psi(t)\rangle\))? Express your answer as a superposition of the \(S_z\) eigenstates \(|+\rangle_z\) and \(|-\rangle_z\).
Show that the probability of a measurement of the energy is time independent for a general state:
\[\left|{\psi(t)}\right\rangle = \sum_n c_n(t) \left|{E_n}\right\rangle \]
that evolves due to a time-independent Hamiltonian.